Question
Answer
$$(6x+8)(5x-8)=30x^2-8x-64$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6x+8)(5x-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}30x^2-48x+40x-64 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}30x^2-8x-64\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6x+8}\right) $ by each term in $ \left( 5x-8\right) $. $$ \left( \color{blue}{6x+8}\right) \cdot \left( 5x-8\right) = 30x^2-48x+40x-64 $$ |
| ② | Combine like terms: $$ 30x^2 \color{blue}{-48x} + \color{blue}{40x} -64 = 30x^2 \color{blue}{-8x} -64 $$ |
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