Answer
$$(6x+5)(6x^2+4x-2)=36x^3+54x^2+8x-10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6x+5)(6x^2+4x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}36x^3+24x^2-12x+30x^2+20x-10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}36x^3+54x^2+8x-10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6x+5}\right) $ by each term in $ \left( 6x^2+4x-2\right) $. $$ \left( \color{blue}{6x+5}\right) \cdot \left( 6x^2+4x-2\right) = 36x^3+24x^2-12x+30x^2+20x-10 $$ |
| ② | Combine like terms: $$ 36x^3+ \color{blue}{24x^2} \color{red}{-12x} + \color{blue}{30x^2} + \color{red}{20x} -10 = 36x^3+ \color{blue}{54x^2} + \color{red}{8x} -10 $$ |
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