Tap the blue circles to see an explanation.
$$ \begin{aligned}(6x-1)(x-2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-12x-x+2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-13x+2\end{aligned} $$ | |
① | Multiply each term of $ \left( \color{blue}{6x-1}\right) $ by each term in $ \left( x-2\right) $. $$ \left( \color{blue}{6x-1}\right) \cdot \left( x-2\right) = 6x^2-12x-x+2 $$ |
② | Combine like terms: $$ 6x^2 \color{blue}{-12x} \color{blue}{-x} +2 = 6x^2 \color{blue}{-13x} +2 $$ |