Answer
$$6x^2-5x-(4x^2-3x+4)=2x^2-2x-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6x^2-5x-(4x^2-3x+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-5x-4x^2+3x-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-2x-4\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 4x^2-3x+4 \right) = -4x^2+3x-4 $$ |
| ② | Combine like terms: $$ \color{blue}{6x^2} \color{red}{-5x} \color{blue}{-4x^2} + \color{red}{3x} -4 = \color{blue}{2x^2} \color{red}{-2x} -4 $$ |
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