Answer
$$(5x-7)(9x^2-4x-8)=45x^3-83x^2-12x+56$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5x-7)(9x^2-4x-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}45x^3-20x^2-40x-63x^2+28x+56 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}45x^3-83x^2-12x+56\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5x-7}\right) $ by each term in $ \left( 9x^2-4x-8\right) $. $$ \left( \color{blue}{5x-7}\right) \cdot \left( 9x^2-4x-8\right) = 45x^3-20x^2-40x-63x^2+28x+56 $$ |
| ② | Combine like terms: $$ 45x^3 \color{blue}{-20x^2} \color{red}{-40x} \color{blue}{-63x^2} + \color{red}{28x} +56 = 45x^3 \color{blue}{-83x^2} \color{red}{-12x} +56 $$ |
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