Tap the blue circles to see an explanation.
$$ \begin{aligned}(5x-4)(3x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}15x^2+10x-12x-8 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}15x^2-2x-8\end{aligned} $$ | |
① | Multiply each term of $ \left( \color{blue}{5x-4}\right) $ by each term in $ \left( 3x+2\right) $. $$ \left( \color{blue}{5x-4}\right) \cdot \left( 3x+2\right) = 15x^2+10x-12x-8 $$ |
② | Combine like terms: $$ 15x^2+ \color{blue}{10x} \color{blue}{-12x} -8 = 15x^2 \color{blue}{-2x} -8 $$ |