Answer
$$5x^2-4x+7-(3x^2+2x-5)=2x^2-6x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5x^2-4x+7-(3x^2+2x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5x^2-4x+7-3x^2-2x+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-6x+12\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 3x^2+2x-5 \right) = -3x^2-2x+5 $$ |
| ② | Combine like terms: $$ \color{blue}{5x^2} \color{red}{-4x} + \color{green}{7} \color{blue}{-3x^2} \color{red}{-2x} + \color{green}{5} = \color{blue}{2x^2} \color{red}{-6x} + \color{green}{12} $$ |
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