Question
Answer
$$(5-4r)(6+3r-2r)=-4r^2-19r+30$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5-4r)(6+3r-2r)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(5-4r)(1r+6) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5r+30-4r^2-24r \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}-4r^2-19r+30\end{aligned} $$ | |
| ① | Combine like terms: $$ 6+ \color{blue}{3r} \color{blue}{-2r} = \color{blue}{r} +6 $$ |
| ② | Multiply each term of $ \left( \color{blue}{5-4r}\right) $ by each term in $ \left( r+6\right) $. $$ \left( \color{blue}{5-4r}\right) \cdot \left( r+6\right) = 5r+30-4r^2-24r $$ |
| ③ | Combine like terms: $$ \color{blue}{5r} +30-4r^2 \color{blue}{-24r} = -4r^2 \color{blue}{-19r} +30 $$ |
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