Answer
$$(4x-8)(3x+5)=12x^2-4x-40$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-8)(3x+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^2+20x-24x-40 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2-4x-40\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-8}\right) $ by each term in $ \left( 3x+5\right) $. $$ \left( \color{blue}{4x-8}\right) \cdot \left( 3x+5\right) = 12x^2+20x-24x-40 $$ |
| ② | Combine like terms: $$ 12x^2+ \color{blue}{20x} \color{blue}{-24x} -40 = 12x^2 \color{blue}{-4x} -40 $$ |
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