Answer
$$(4n+5)(5n-1)=20n^2+21n-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4n+5)(5n-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20n^2-4n+25n-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20n^2+21n-5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4n+5}\right) $ by each term in $ \left( 5n-1\right) $. $$ \left( \color{blue}{4n+5}\right) \cdot \left( 5n-1\right) = 20n^2-4n+25n-5 $$ |
| ② | Combine like terms: $$ 20n^2 \color{blue}{-4n} + \color{blue}{25n} -5 = 20n^2+ \color{blue}{21n} -5 $$ |
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