Answer
$$(4n-8)(2n-3)=8n^2-28n+24$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4n-8)(2n-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8n^2-12n-16n+24 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8n^2-28n+24\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4n-8}\right) $ by each term in $ \left( 2n-3\right) $. $$ \left( \color{blue}{4n-8}\right) \cdot \left( 2n-3\right) = 8n^2-12n-16n+24 $$ |
| ② | Combine like terms: $$ 8n^2 \color{blue}{-12n} \color{blue}{-16n} +24 = 8n^2 \color{blue}{-28n} +24 $$ |
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