Answer
$$(4m+n)(m-2n)=4m^2-7mn-2n^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4m+n)(m-2n)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4m^2-8mn+mn-2n^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4m^2-7mn-2n^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4m+n}\right) $ by each term in $ \left( m-2n\right) $. $$ \left( \color{blue}{4m+n}\right) \cdot \left( m-2n\right) = 4m^2-8mn+mn-2n^2 $$ |
| ② | Combine like terms: $$ 4m^2 \color{blue}{-8mn} + \color{blue}{mn} -2n^2 = 4m^2 \color{blue}{-7mn} -2n^2 $$ |
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