$$ \begin{aligned}(4cd)^2(-3d^2)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16c^2d^2\cdot-27d^6 \xlongequal{ } \\[1 em] & \xlongequal{ }-432c^2d^8\end{aligned} $$ | |
① | $$ \left( 4cd \right)^2 = 4^2c^2d^2 = 16c^2d^2 $$$$ \left( -3d^2 \right)^3 = (-3)^3 \left( d^2 \right)^3 = -27d^6 $$ |