Answer
$$(4a+2b)(5a+3b)=20a^2+22ab+6b^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4a+2b)(5a+3b)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20a^2+12ab+10ab+6b^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20a^2+22ab+6b^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4a+2b}\right) $ by each term in $ \left( 5a+3b\right) $. $$ \left( \color{blue}{4a+2b}\right) \cdot \left( 5a+3b\right) = 20a^2+12ab+10ab+6b^2 $$ |
| ② | Combine like terms: $$ 20a^2+ \color{blue}{12ab} + \color{blue}{10ab} +6b^2 = 20a^2+ \color{blue}{22ab} +6b^2 $$ |
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