Answer
$$(4a+1)(a^2-2a-3)=4a^3-7a^2-14a-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4a+1)(a^2-2a-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4a^3-8a^2-12a+a^2-2a-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4a^3-7a^2-14a-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4a+1}\right) $ by each term in $ \left( a^2-2a-3\right) $. $$ \left( \color{blue}{4a+1}\right) \cdot \left( a^2-2a-3\right) = 4a^3-8a^2-12a+a^2-2a-3 $$ |
| ② | Combine like terms: $$ 4a^3 \color{blue}{-8a^2} \color{red}{-12a} + \color{blue}{a^2} \color{red}{-2a} -3 = 4a^3 \color{blue}{-7a^2} \color{red}{-14a} -3 $$ |
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