Answer
$$(3y+1)^3=27y^3+27y^2+9y+1$$
Explanation
| $$ \begin{aligned}(3y+1)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27y^3+27y^2+9y+1\end{aligned} $$ | |
| ① | Find $ \left(3y+1\right)^3 $ using formula $$ (A + B) = A^3 + 3A^2B + 3AB^2 + B^3 $$where $ A = 3y $ and $ B = 1 $. $$ \left(3y+1\right)^3 = \left( 3y \right)^3+3 \cdot \left( 3y \right)^2 \cdot 1 + 3 \cdot 3y \cdot 1^2+1^3 = 27y^3+27y^2+9y+1 $$ |
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