Answer
$$(3x+8)(3x-8)=9x^2-64$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x+8)(3x-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2-24x+24x-64 \xlongequal{ } \\[1 em] & \xlongequal{ }9x^2 -\cancel{24x}+ \cancel{24x}-64 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9x^2-64\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x+8}\right) $ by each term in $ \left( 3x-8\right) $. $$ \left( \color{blue}{3x+8}\right) \cdot \left( 3x-8\right) = 9x^2 -\cancel{24x}+ \cancel{24x}-64 $$ |
| ② | Combine like terms: $$ 9x^2 \, \color{blue}{ -\cancel{24x}} \,+ \, \color{blue}{ \cancel{24x}} \,-64 = 9x^2-64 $$ |
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