Answer
$$(3x+4)(2x+3)=6x^2+17x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x+4)(2x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2+9x+8x+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2+17x+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x+4}\right) $ by each term in $ \left( 2x+3\right) $. $$ \left( \color{blue}{3x+4}\right) \cdot \left( 2x+3\right) = 6x^2+9x+8x+12 $$ |
| ② | Combine like terms: $$ 6x^2+ \color{blue}{9x} + \color{blue}{8x} +12 = 6x^2+ \color{blue}{17x} +12 $$ |
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