Answer
$$(3x-7)(3x-5)=9x^2-36x+35$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-7)(3x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2-15x-21x+35 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}9x^2-36x+35\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-7}\right) $ by each term in $ \left( 3x-5\right) $. $$ \left( \color{blue}{3x-7}\right) \cdot \left( 3x-5\right) = 9x^2-15x-21x+35 $$ |
| ② | Combine like terms: $$ 9x^2 \color{blue}{-15x} \color{blue}{-21x} +35 = 9x^2 \color{blue}{-36x} +35 $$ |
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