Tap the blue circles to see an explanation.
$$ \begin{aligned}(3x-6)(7x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}21x^2+6x-42x-12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}21x^2-36x-12\end{aligned} $$ | |
① | Multiply each term of $ \left( \color{blue}{3x-6}\right) $ by each term in $ \left( 7x+2\right) $. $$ \left( \color{blue}{3x-6}\right) \cdot \left( 7x+2\right) = 21x^2+6x-42x-12 $$ |
② | Combine like terms: $$ 21x^2+ \color{blue}{6x} \color{blue}{-42x} -12 = 21x^2 \color{blue}{-36x} -12 $$ |