$$ \begin{aligned}(3x-4)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^2-24x+16\end{aligned} $$ | |
① | Find $ \left(3x-4\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 3x } $ and $ B = \color{red}{ 4 }$. $$ \begin{aligned}\left(3x-4\right)^2 = \color{blue}{\left( 3x \right)^2} -2 \cdot 3x \cdot 4 + \color{red}{4^2} = 9x^2-24x+16\end{aligned} $$ |