Question
Answer
$$(3x-4)(2x-3)=6x^2-17x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-4)(2x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-9x-8x+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-17x+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-4}\right) $ by each term in $ \left( 2x-3\right) $. $$ \left( \color{blue}{3x-4}\right) \cdot \left( 2x-3\right) = 6x^2-9x-8x+12 $$ |
| ② | Combine like terms: $$ 6x^2 \color{blue}{-9x} \color{blue}{-8x} +12 = 6x^2 \color{blue}{-17x} +12 $$ |
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