Answer
$$(3x-2)(x-7)=3x^2-23x+14$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-2)(x-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^2-21x-2x+14 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3x^2-23x+14\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-2}\right) $ by each term in $ \left( x-7\right) $. $$ \left( \color{blue}{3x-2}\right) \cdot \left( x-7\right) = 3x^2-21x-2x+14 $$ |
| ② | Combine like terms: $$ 3x^2 \color{blue}{-21x} \color{blue}{-2x} +14 = 3x^2 \color{blue}{-23x} +14 $$ |
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