Answer
$$(3x^5+y)^2=9x^{10}+6x^5y+y^2$$
Explanation
| $$ \begin{aligned}(3x^5+y)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}9x^{10}+6x^5y+y^2\end{aligned} $$ | |
| ① | Find $ \left(3x^5+y\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 3x^5 } $ and $ B = \color{red}{ y }$. $$ \begin{aligned}\left(3x^5+y\right)^2 = \color{blue}{\left( 3x^5 \right)^2} +2 \cdot 3x^5 \cdot y + \color{red}{y^2} = 9x^{10}+6x^5y+y^2\end{aligned} $$ |
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