Answer
$$(3x^3+5)(x^2-8)=3x^5-24x^3+5x^2-40$$
Explanation
| $$ \begin{aligned}(3x^3+5)(x^2-8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^5-24x^3+5x^2-40\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x^3+5}\right) $ by each term in $ \left( x^2-8\right) $. $$ \left( \color{blue}{3x^3+5}\right) \cdot \left( x^2-8\right) = 3x^5-24x^3+5x^2-40 $$ |
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