Answer
$$3x^2y+2xy^2-3xy+4x+3xy^2-2x^2y+xy-3y=x^2y+5xy^2-2xy+4x-3y$$
Explanation
| $$ \begin{aligned}3x^2y+2xy^2-3xy+4x+3xy^2-2x^2y+xy-3y& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x^2y+5xy^2-2xy+4x-3y\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{3x^2y} + \color{red}{2xy^2} \color{green}{-3xy} +4x+ \color{red}{3xy^2} \color{blue}{-2x^2y} + \color{green}{xy} -3y = \color{blue}{x^2y} + \color{red}{5xy^2} \color{green}{-2xy} +4x-3y $$ |
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