Answer
$$(3+7x)(9x-5)=63x^2-8x-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3+7x)(9x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27x-15+63x^2-35x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}63x^2-8x-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3+7x}\right) $ by each term in $ \left( 9x-5\right) $. $$ \left( \color{blue}{3+7x}\right) \cdot \left( 9x-5\right) = 27x-15+63x^2-35x $$ |
| ② | Combine like terms: $$ \color{blue}{27x} -15+63x^2 \color{blue}{-35x} = 63x^2 \color{blue}{-8x} -15 $$ |
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