Answer
$$\frac{(3p^3)^3}{q^7}=\frac{27p^9}{q^7}$$
Explanation
| $$ \begin{aligned}\frac{(3p^3)^3}{q^7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{27p^9}{q^7}\end{aligned} $$ | |
| ① | $$ \left( 3p^3 \right)^3 = 3^3 \left( p^3 \right)^3 = 27p^9 $$ |
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