Answer
$$(3n-x)^3=27n^3-27n^2x+9nx^2-x^3$$
Explanation
| $$ \begin{aligned}(3n-x)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27n^3-27n^2x+9nx^2-x^3\end{aligned} $$ | |
| ① | Find $ \left(3n-x\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = 3n $ and $ B = x $. $$ \left(3n-x\right)^3 = \left( 3n \right)^3-3 \cdot \left( 3n \right)^2 \cdot x + 3 \cdot 3n \cdot x^2-x^3 = 27n^3-27n^2x+9nx^2-x^3 $$ |
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