Answer
$$(3a-5)(2a\cdot2-4a)=0$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3a-5)(2a\cdot2-4a)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(3a-5)(4a-4a) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}(3a-5)\cdot0 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}0a+0 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}0\end{aligned} $$ | |
| ① | $$ 2 a \cdot 2 = 4 a $$ |
| ② | Combine like terms: $$ \, \color{blue}{ \cancel{4a}} \, \, \color{blue}{ -\cancel{4a}} \, = 0 $$ |
| ③ | $$ \left( \color{blue}{3a-5}\right) \cdot 0 = 0a0 $$ |
| ④ | Combine like terms: $$ 0 = 0 $$ |
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