Answer
$$(3a-5)(2a-4a)=-6a^2+10a$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3a-5)(2a-4a)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}(3a-5)\cdot-2a \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-6a^2+10a\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{2a} \color{blue}{-4a} = \color{blue}{-2a} $$ |
| ② | $$ \left( \color{blue}{3a-5}\right) \cdot -2a = -6a^2+10a $$ |
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