Answer
$$(3a-5)(2a^2-4a)=6a^3-22a^2+20a$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3a-5)(2a^2-4a)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6a^3-12a^2-10a^2+20a \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6a^3-22a^2+20a\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3a-5}\right) $ by each term in $ \left( 2a^2-4a\right) $. $$ \left( \color{blue}{3a-5}\right) \cdot \left( 2a^2-4a\right) = 6a^3-12a^2-10a^2+20a $$ |
| ② | Combine like terms: $$ 6a^3 \color{blue}{-12a^2} \color{blue}{-10a^2} +20a = 6a^3 \color{blue}{-22a^2} +20a $$ |
This page was created using
Simplify polynomials calculator