Answer
$$(2x+1)(2x-1)=4x^2-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x+1)(2x-1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2-2x+2x-1 \xlongequal{ } \\[1 em] & \xlongequal{ }4x^2 -\cancel{2x}+ \cancel{2x}-1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-1\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x+1}\right) $ by each term in $ \left( 2x-1\right) $. $$ \left( \color{blue}{2x+1}\right) \cdot \left( 2x-1\right) = 4x^2 -\cancel{2x}+ \cancel{2x}-1 $$ |
| ② | Combine like terms: $$ 4x^2 \, \color{blue}{ -\cancel{2x}} \,+ \, \color{blue}{ \cancel{2x}} \,-1 = 4x^2-1 $$ |
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