Answer
$$(2x-5)(3x+1)=6x^2-13x-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-5)(3x+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2+2x-15x-5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-13x-5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-5}\right) $ by each term in $ \left( 3x+1\right) $. $$ \left( \color{blue}{2x-5}\right) \cdot \left( 3x+1\right) = 6x^2+2x-15x-5 $$ |
| ② | Combine like terms: $$ 6x^2+ \color{blue}{2x} \color{blue}{-15x} -5 = 6x^2 \color{blue}{-13x} -5 $$ |
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