$$ \begin{aligned}(2x-3)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^3-36x^2+54x-27\end{aligned} $$ | |
① | Find $ \left(2x-3\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = 2x $ and $ B = 3 $. $$ \left(2x-3\right)^3 = \left( 2x \right)^3-3 \cdot \left( 2x \right)^2 \cdot 3 + 3 \cdot 2x \cdot 3^2-3^3 = 8x^3-36x^2+54x-27 $$ |