Answer
$$(2x-3)(x-4)=2x^2-11x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-3)(x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2-8x-3x+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^2-11x+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-3}\right) $ by each term in $ \left( x-4\right) $. $$ \left( \color{blue}{2x-3}\right) \cdot \left( x-4\right) = 2x^2-8x-3x+12 $$ |
| ② | Combine like terms: $$ 2x^2 \color{blue}{-8x} \color{blue}{-3x} +12 = 2x^2 \color{blue}{-11x} +12 $$ |
This page was created using
Simplify polynomials calculator