Answer
$$(2x-11)(3x-7)=6x^2-47x+77$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x-11)(3x-7)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-14x-33x+77 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-47x+77\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2x-11}\right) $ by each term in $ \left( 3x-7\right) $. $$ \left( \color{blue}{2x-11}\right) \cdot \left( 3x-7\right) = 6x^2-14x-33x+77 $$ |
| ② | Combine like terms: $$ 6x^2 \color{blue}{-14x} \color{blue}{-33x} +77 = 6x^2 \color{blue}{-47x} +77 $$ |
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