Answer
$$(2x^3+y^5)^2=y^{10}+4x^3y^5+4x^6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x^3+y^5)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^6+4x^3y^5+y^{10} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}y^{10}+4x^3y^5+4x^6\end{aligned} $$ | |
| ① | Find $ \left(2x^3+y^5\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2x^3 } $ and $ B = \color{red}{ y^5 }$. $$ \begin{aligned}\left(2x^3+y^5\right)^2 = \color{blue}{\left( 2x^3 \right)^2} +2 \cdot 2x^3 \cdot y^5 + \color{red}{\left( y^5 \right)^2} = 4x^6+4x^3y^5+y^{10}\end{aligned} $$ |
| ② | Combine like terms: $$ y^{10}+4x^3y^5+4x^6 = y^{10}+4x^3y^5+4x^6 $$ |
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