Answer
$$2x^2y-3y+4x^2-(7xy^2+x^2-5x^2y)=7x^2y-7xy^2+3x^2-3y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2x^2y-3y+4x^2-(7xy^2+x^2-5x^2y)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2y-3y+4x^2-7xy^2-x^2+5x^2y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}7x^2y-7xy^2+3x^2-3y\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 7xy^2+x^2-5x^2y \right) = -7xy^2-x^2+5x^2y $$ |
| ② | Combine like terms: $$ \color{blue}{2x^2y} -3y+ \color{red}{4x^2} -7xy^2 \color{red}{-x^2} + \color{blue}{5x^2y} = \color{blue}{7x^2y} -7xy^2+ \color{red}{3x^2} -3y $$ |
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