Answer
$$(2x^2-y^5)^2=y^{10}-4x^2y^5+4x^4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2x^2-y^5)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^4-4x^2y^5+y^{10} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}y^{10}-4x^2y^5+4x^4\end{aligned} $$ | |
| ① | Find $ \left(2x^2-y^5\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2x^2 } $ and $ B = \color{red}{ y^5 }$. $$ \begin{aligned}\left(2x^2-y^5\right)^2 = \color{blue}{\left( 2x^2 \right)^2} -2 \cdot 2x^2 \cdot y^5 + \color{red}{\left( y^5 \right)^2} = 4x^4-4x^2y^5+y^{10}\end{aligned} $$ |
| ② | Combine like terms: $$ y^{10}-4x^2y^5+4x^4 = y^{10}-4x^2y^5+4x^4 $$ |
This page was created using
Simplify polynomials calculator