Answer
$$2x^2-4x+3y-6+4y^2-3x-7y+4=2x^2+4y^2-7x-4y-2$$
Explanation
| $$ \begin{aligned}2x^2-4x+3y-6+4y^2-3x-7y+4& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2+4y^2-7x-4y-2\end{aligned} $$ | |
| ① | Combine like terms: $$ 2x^2 \color{blue}{-4x} + \color{red}{3y} \color{green}{-6} +4y^2 \color{blue}{-3x} \color{red}{-7y} + \color{green}{4} = 2x^2+4y^2 \color{blue}{-7x} \color{red}{-4y} \color{green}{-2} $$ |
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