Answer
$$(2m^2+8m+6)(6m^2-7m+8)=12m^4+34m^3-4m^2+22m+48$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2m^2+8m+6)(6m^2-7m+8)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12m^4+34m^3-4m^2+22m+48\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2m^2+8m+6}\right) $ by each term in $ \left( 6m^2-7m+8\right) $. $$ \left( \color{blue}{2m^2+8m+6}\right) \cdot \left( 6m^2-7m+8\right) = 12m^4-14m^3+16m^2+48m^3-56m^2+64m+36m^2-42m+48 $$ |
| ② | Combine like terms: $$ 12m^4 \color{blue}{-14m^3} + \color{red}{16m^2} + \color{blue}{48m^3} \color{green}{-56m^2} + \color{orange}{64m} + \color{green}{36m^2} \color{orange}{-42m} +48 = \\ = 12m^4+ \color{blue}{34m^3} \color{green}{-4m^2} + \color{orange}{22m} +48 $$ |
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