Answer
$$(2k^2+1)^2=4k^4+4k^2+1$$
Explanation
| $$ \begin{aligned}(2k^2+1)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4k^4+4k^2+1\end{aligned} $$ | |
| ① | Find $ \left(2k^2+1\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 2k^2 } $ and $ B = \color{red}{ 1 }$. $$ \begin{aligned}\left(2k^2+1\right)^2 = \color{blue}{\left( 2k^2 \right)^2} +2 \cdot 2k^2 \cdot 1 + \color{red}{1^2} = 4k^4+4k^2+1\end{aligned} $$ |
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