Answer
$$(2a-4b)(7a-2b)=14a^2-32ab+8b^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(2a-4b)(7a-2b)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}14a^2-4ab-28ab+8b^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}14a^2-32ab+8b^2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{2a-4b}\right) $ by each term in $ \left( 7a-2b\right) $. $$ \left( \color{blue}{2a-4b}\right) \cdot \left( 7a-2b\right) = 14a^2-4ab-28ab+8b^2 $$ |
| ② | Combine like terms: $$ 14a^2 \color{blue}{-4ab} \color{blue}{-28ab} +8b^2 = 14a^2 \color{blue}{-32ab} +8b^2 $$ |
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