Tap the blue circles to see an explanation.
$$ \begin{aligned}(2-x)\cdot(7-x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}14-2x-7x+x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}x^2-9x+14\end{aligned} $$ | |
① | Multiply each term of $ \left( \color{blue}{2-x}\right) $ by each term in $ \left( 7-x\right) $. $$ \left( \color{blue}{2-x}\right) \cdot \left( 7-x\right) = 14-2x-7x+x^2 $$ |
② | Combine like terms: $$ 14 \color{blue}{-2x} \color{blue}{-7x} +x^2 = x^2 \color{blue}{-9x} +14 $$ |