Answer
$$16z^2-24z+9-(z^2+4z+4)=15z^2-28z+5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}16z^2-24z+9-(z^2+4z+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16z^2-24z+9-z^2-4z-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}15z^2-28z+5\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( z^2+4z+4 \right) = -z^2-4z-4 $$ |
| ② | Combine like terms: $$ \color{blue}{16z^2} \color{red}{-24z} + \color{green}{9} \color{blue}{-z^2} \color{red}{-4z} \color{green}{-4} = \color{blue}{15z^2} \color{red}{-28z} + \color{green}{5} $$ |
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