Answer
$$(1-b)^2=b^2-2b+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(1-b)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1-2b+b^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^2-2b+1\end{aligned} $$ | |
| ① | Find $ \left(1-b\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 1 } $ and $ B = \color{red}{ b }$. $$ \begin{aligned}\left(1-b\right)^2 = \color{blue}{1^2} -2 \cdot 1 \cdot b + \color{red}{b^2} = 1-2b+b^2\end{aligned} $$ |
| ② | Combine like terms: $$ b^2-2b+1 = b^2-2b+1 $$ |
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