Answer
$$(1-4b)^3=-64b^3+48b^2-12b+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(1-4b)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1-12b+48b^2-64b^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-64b^3+48b^2-12b+1\end{aligned} $$ | |
| ① | Find $ \left(1-4b\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = 1 $ and $ B = 4b $. $$ \left(1-4b\right)^3 = 1^3-3 \cdot 1^2 \cdot 4b + 3 \cdot 1 \cdot \left( 4b \right)^2-\left( 4b \right)^3 = 1-12b+48b^2-64b^3 $$ |
| ② | Combine like terms: $$ -64b^3+48b^2-12b+1 = -64b^3+48b^2-12b+1 $$ |
This page was created using
Simplify polynomials calculator