Answer
$$(-8a^2-1)(3a^2-5)=-24a^4+37a^2+5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-8a^2-1)(3a^2-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-24a^4+40a^2-3a^2+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-24a^4+37a^2+5\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-8a^2-1}\right) $ by each term in $ \left( 3a^2-5\right) $. $$ \left( \color{blue}{-8a^2-1}\right) \cdot \left( 3a^2-5\right) = -24a^4+40a^2-3a^2+5 $$ |
| ② | Combine like terms: $$ -24a^4+ \color{blue}{40a^2} \color{blue}{-3a^2} +5 = -24a^4+ \color{blue}{37a^2} +5 $$ |
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