Answer
$$(-12-a)\cdot(4-a)+60=a^2+8a+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(-12-a)\cdot(4-a)+60& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-48+12a-4a+a^2+60 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}a^2+8a+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{-12-a}\right) $ by each term in $ \left( 4-a\right) $. $$ \left( \color{blue}{-12-a}\right) \cdot \left( 4-a\right) = -48+12a-4a+a^2 $$ |
| ② | Combine like terms: $$ \color{blue}{-48} + \color{red}{12a} \color{red}{-4a} +a^2+ \color{blue}{60} = a^2+ \color{red}{8a} + \color{blue}{12} $$ |
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